Question

in the adjoining figure,ABCD is a rectangle in which AB=18 cm,BC=8cm and DE=10 cm.find the area of the shaded region EBCD.

Figure given above!

Answer 1

120 cm square will be the answer

Answer 2

Answer:

Step-by-step explanation:

From the given figure, AD=8cm, DE=10 cm, CB=10 cm and AB=18 cm.

Using the Pythagoras theorem in ΔADE, we have

$(DE)^{2}=(AE)^{2}+(DA)^{2}$

$(10)^2=(AE)^2+(8)^2$

$100-64=(AE)^2$

$AE=6 cm$

Now, areaof the shaded region is= area of rectangle ADCB-area of triangle ADE

$A=l{\times}b-\frac{1}{2}{\times}base{\times}height$

$A=8{\times}18-\frac{1}{2}{\times}6{\times}8$

$A=144-24$

$A=120cm^2$