Question

In the adjoining
figure, ABCD is a rectangle whose diagonals AC and
BD intersect at 0. If ZAOB = 110°, find the measure of :
(1) ZODA and (ii) ZOCD.
(Hint: ZAOD = (180° - 110°) = 70°.
Since OA = OD, we have ZOAD = ZODA.
COD = 110° (Why?) and OC = OD, so ZOCD = ZODC.)
Pls solve the 6th questions

Answer 1

Answer:

angle AOB+angle AOD=180

angle AOD=180+110=70°

diagonal of rectangle are equal and bisect each other

OA=OD

angleOAD=angle=ODA

angleOAD+angle ODA+angle AOD=180

2angle ODA=180-70

2angle ODA=110

angle ODA=55°

b)

OD=OC

angleODC= angleOCD

angle COD=110(vertically opposite to angle AOB)

angleODC+angleOCD+angleCOD=180

2angleOCD=180-110

2angleOCD=70

angleOCD=35°

Answer 2

Answer:

upper answer is correct