Question

In the adjoining figure, ABCD is a rectangle whose diagonals AC and
BD intersect at O. If angle AOB = 110°, find the measure of:
о
(i) angle ODA and (ii) angle OCD.
Hint: angle AOD = (180° - 110°) = 70°.
Since OA = OD, we have angle OAD = angle ODA.
angle COD = 110° (Why?) and OC = OD, so angle OCD = angle ODC.)​

Answer 1

Angle ODA and ODC is 55 degree