Math, asked by sohini2034, 8 months ago

In the adjoining figure, ABCD is a rhombus in which <BAC=40°. Find the measures of:
(I)<ACB (ii) <ABC (III) <ADC (iv)<ACD (v)<CAD.
Please answer this question as fast as possible.​

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Answered by kakoliroy2009
73

Answer:

here's ur answer

<BAC=<DCA=40°(alternate angles)

<DCA=<ACB=40°(diagonals bisects the opp. vertex angles)

<BAC+<ABC+<ACB=180° (angle sum property of triangle)

<ABC=100°

<BAC=<DAC=40°(diagonals bisect the opposite vertex angle)

<DAC+<ACD+<ADC=180°(angle sum property of triangle)

<ADC=100°

<ACB=<ACD=40°(diagonals bisect the opposite vertex angle)

i <ACB=40°

ii <ABC=100°

iii<ADC=100°

iv<ACD=40°

v<CAD=40°

hope it helps

Answered by ny39929
24

Step-by-step explanation:

Hope the answer is helpful

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