Question

In the adjoining figure ABCD is a square and triangle EDC is equilateral triangle prove that AE= BE

Answer 1

In fig⬜ ABCD is square
So AE =CE eq 1
BE =DE eq2 diagonals of square bisects each other
Triangle EDC is equilateral triangle
So ED=DC=EC eq3
SO from eq 1 2 3
AE=BE
IS PROVED
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