Question

in the adjoining figure ABCD is a trapezium ab parallel CD and its area is 33 CM Square from the information given in the figure find the length of all sides of the ABCD tell me this question answer plezz fast ​

Answer 1

Answer:

x=

Step-by-step explanation:

area of trapezium =1/2*h*(sum of ll sides)

=1/2*x-4*(x+2x+1)=33

x-4(3x+1)=33*2

sorry

Answer 2

Step-by-step explanation:

area of trapezium = 1/2 × h × (a + b)

h is the height, a and b are the parallel side of the trapezium

a = 2x + 1

b = x

h = x - 4

area of trapezium. = 33 sq cm

$33 = \frac{1}{2} \times (x - 4) \times (2x + 1 + x) \\ 33 \times 2 = (x - 4)(3x + 1) \\ 66 = 3 {x}^{2} + x - 12x - 4 \\ 66 = 3{x}^{2} - 11x - 4 \\ 3 {x}^{2} - 11x - 4 - 66 = 0 \\ 3 {x}^{2} - 11x - 70 = 0 \\ 3 {x}^{2} - 21x + 10x - 70 = 0 \\ 3x(x - 7) + 10(x - 7) = 0 \\ (x - 7)(3x + 10) = 0 \\ x - 7 = 0 \: \: \: \: 3x + 10 = 0 \\ x = 7 \: \: \: \: \: \: x = - \frac{10}{3}$

as length cannot be negative we take x = 7

AB = x = 7cm

CD = 2x + 1 = 2(7) + 1 = 14 + 1 = 15 cm

AD = BC = x - 2 = 7 - 2 = 5 cm

AM = x - 4 = 7 - 4 = 3 cm

hope you get your answer