In the adjoining figure ABCD is a trapezium. If angle A : angle D=5:7, B= (3x+11)° and angle C= 5x-31)°, then find all the angles of the trapezium
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Answer:
A=75°
B=86°
C=94°
D=105°
Explanation:
Let A=5y andD=7y
A+D=180° [property of trapezium]
=>5y+7y=180°
=>y=15
Therefore, A=75° andD=105°
Also B+C=180° [property of trapezium]
=>3x+11+5x-31=180°
=>8x-20=180°
=>8x=200°
=>x=25
Therefore, B=(3×25)+11=86° and C=(5×25)-31=94°
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