Question

In the adjoining figure, ABCD is an isosceles trapezium in
which

BCD = 2x and

ABC = 3x. Find all the angles of

the trapezium.(

Answer 1

Answer:

72° , 108° , 72° , 108°

Step-by-step explanation:

Given that ABCD is an isosceles trapezium .

So, angle ADC = angle BCD ........ (i)

and angle DAB = angle ABC.......(ii)

Since ABCD is a trapezium, so, AB II CD

Now, consider AB II CD, BC transversal.

So, angle BCD + angle ABC = 180° {alternate interior angles}

Now, put the values

2x + 3x = 180°

or, 5x = 180°

or, x = 36°

So, all the angles are 72° , 108° , 72° , 108°