Question

In the adjoining figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE.

Answer 1

In ABC & ADE,

∠BAD=∠EAC(GIVEN) (ADD ∠DAC Both side)

∠BAC=∠DAE

AC=AE{GIVEN}

AB=AB{GIVEN}

ABC≅ADE(SAS criterion)

BC=DE(cpct)

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Answer 2

Answer:

Answer is in the pic Hope it helps you