Question

In the adjoining figure, AC & BD intersect at O.

If AB = CB, AD = CD and AO=OC.

The angle congruent to AOB is

<AOD
<COB
<COD
<DOA​

Answer 1

Answer:

<COB

Step-by-step explanation:

in the given figure:

line segments AB and BC are shown equal.

So ABC is an isosceles triangle.

OB in the figure is the height / altitude of ABC

(an altitude always cuts the side opposite to the vertex of its emergence by 90 degrees )

thus angle BOA = 90 degrees

AB = CB

OB = BO (if we take BOA and COB as two triangles)

So by CPCT : angle BOC is equal to given angle AOB

I am not good with steps formation but i hope this helps

If you didn't know.....

CPCT = Corresponding Parts of Congruent Triangles.