In the adjoining figure, AD = 4cm , BD = 3cm and CB = 12cm then, Find
(a) The length of AB
(b) Value of Cot Ѳ
(c) Value of Sec α
(d) The length of AC
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Answered by
0
Answer:
hey, buddy here is your answer
Step-by-step explanation:
a) (AB)^2= (AD)^2+(AB)^2
(AB)^2= 4^2+3^2
(AB)^2= 25
AB= 5
Option (3)
b) Cot theta =12/13
c) Sec a = 13/5
d) (AC)^2=(AB)^2 + (BC)^2
AC^2= 144+25
AC = 13
e) Cos theta/Cos a =12/13/5/13
= 12/5
hope it helps you
Answered by
1
Answer:
- c
- d
- a
- a
- b
- b
Step-by-step explanation:
please give me 10 thanks please
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