Question

In the adjoining figure ad and be are the medians of triangle abc and df parallel to be show that cf = 1/4ac

Answer 1

Answer:

Consider ΔABC

Since AD is Median ⟹BD=BC⋯(1)

Since BE is Median ⟹AE=EC⋯(2)

Consider ΔBEC

Since BE∣∣DF

By Basic Proportionality theorm,

⟹

DC

BD

=

FC

EF

From (1)

⟹CF=EF

⟹CF=

2

1

AE

From (2)

⟹CF=

4

1

AC

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