Question

in the adjoining figure AD=BC and BD=AC
prove that : Angle ADB = angle BCA and angle DAB = angle CBA.


pls answer this question ASAP​

Answer 1

Step-by-step explanation:

Given,

AD = BC

BD = CA

To Prove- ∠ADB = ∠BCA and ∠DAB = ∠CBA.

Proof- Let us take ∆ADB and ∆BCA into consideration .

AD = BC (Given)

BD = AC (Given)

AB = AB (Common side)

∴∆ADB ≅ ∆BCA by SSS

SSS(side-side-side) congruence states that if two triangles have all the three sides equal they are congruent.

Now , Applying CPCT( Corresponding parts of congruent triangles) which states that, If two triangles are congruent then their corresponding sides are equal , also corresponding angles too.

∠ADB = ∠BCA

Similarly , ∠DAB = ∠CBA

Hence proved.

Answer 2

Step-by-step explanation:

RAS niyam se hence proved it

DAB=CBA