Question

in the adjoining figure , AD bisects ㄥA and AD ┻BC. Prove that a) ΔADB ≈ and ΔADC and b) ㄥB=ㄥC

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Answer 1

Answer:

so,bd= cd

Step-by-step explanation:

As, AD is bisector of ∠A,

⇒∠BAD≅∠CAD

∠ADB≅∠ADC=90

o

⋯⋯[∵it is given that AD⊥BC]

And AD=AD⋯⋯[common side]

So, by ASA test

ΔABD≅ΔACD.

Corresponding sides of congruent triangles are equal.

So, BD=CD

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