In the adjoining figure, AD : DC = 2:3, then ZABC
is equal to
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Step-by-step explanation:
AS we need B at unit place and A at ten’s place,
∴ B = 0 as 3 × 0 = 0
Now we want to find A, 3 × A = A (at unit’s place)
∴ A = 5, as 3 × 5 = 15
∴ c = 1
50
×3
150
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