Question

In the adjoining figure,
AD I BC, AB = C,
AC = b, BC = a, CD = x
Prove that: c2 = a + b2 - 2ax.​

Answer 1

Step-by-step explanation:

as ADC will be isosceles triangle, CD=AD=x,AC will be common for both the triangles ABC, ADC..

if CD = AD so I can say A =C=2c...

now a = BC, b=AC...

now as ACD and ABC are isosceles triangle so CD = AD and BC = AC, so I can write 2 of CD and 2 of AC= BAC= A and DCA=C so 2 of ax now as ac =BC and ac=b so b2 by this we can say c2=a+b2-2ax as we can compare both triangles as they both are isosceles triangles.. hence proved...