in the adjoining figure, AD is a median of ∆ ABC and DE || BA . show that BE is also a median of ∆ ABC
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Given :-
- In ∆ ABC, AD is a median and DE || BA.
To Prove :-
- BE is also a median of ∆ ABC. (That means require to prove E is the midpoint of AC.)
Concept Used :-
- Converse of Midpoint theorem - states that "if a line is drawn through the midpoint of one side of a triangle, and parallel to the other side, it bisects the third side”.
- Median - Median is the line segment from a vertex to the midpoint of the opposite side.
Proof :-
Given that
- In ∆ ABC,
- AD is median
- ⇛ D is the midpoint of BC.
Now,
Again,
- In ∆ ABC,
- D is the midpoint of BC. [ Proved above ]
- and DE || BC [ Given ]
So,
By Converse of Midpoint Theorem,
- E is the midpoint of AC.
Hence,
- BE is median of ∆ ABC.
Additional Information :-
Midpoint Theorem -
states that “The line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side.”
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ㅤㅤㅤㅤ❈Question:-
- in the adjoining figure, AD is a median of ∆ ABC and DE || BA . show that BE is also a median of ∆ ABC
ㅤㅤㅤㅤ✲Given :-
- In ∆ ABC, AD is a median and DE || BA.
ㅤㅤㅤㅤ✯To Prove :-
- BE is also a median of ∆ ABC.
ㅤㅤㅤㅤ✾Solution:-
In ΔABC
➟It is given that DE || AB.
➟We know that D is the midpoint of BC ㅤㅤㅤㅤㅤㅤㅤ_______based on mid point theorem
- E is the mid point of AC
Hence Proved that BE is also a median of ∆ ABC.
╾╾╾╾╾╾╾╾╾╾╾╾╾╾╾╾╾╾╾╾╾
Learn More:-✔
- The midpoint theorem states that “The line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side.”
- The line drawn through the midpoint of one side of a triangle, parallel to another side bisects the third side.
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