Question

In the adjoining figure , AD is bisector of /_ BAC .If AB=6cm , AB=4cm,BD=3cm , find BC​

Answer 1

Step-by-step explanation:

Here we can see that

$\angle \: BAC \:$

is bisected by AD where AD touches BC at D.

$important \: points = >$

BC=BD+DC,

$where \: BC = 3 \:cm$

also given the adjasent sides ,

AB=6cm. and AC = 5cm.

from angle bisector theorem ,

it satisfied that,

$\frac{AB}{BD} = \frac{AC}{DC} \:$

$DC= \frac{AC \times BD}{AB} \\ = \frac{5 \times 3}{6} \\ = 2.5cm \:$

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Answer 2

Step-by-step explanation:

Here we can see that

\angle \: BAC \:∠BAC

is bisected by AD where AD touches BC at D.

important \: points = >importantpoints=>

BC=BD+DC,

where \: BC = 3 \:cmwhereBC=3cm

also given the adjasent sides ,

AB=6cm. and AC = 5cm.

from angle bisector theorem ,

it satisfied that,

\frac{AB}{BD} = \frac{AC}{DC} \:BDAB=DCAC

\begin{gathered}DC= \frac{AC \times BD}{AB} \\ = \frac{5 \times 3}{6} \\ = 2.5cm \:\end{gathered}DC=ABAC×BD=65×3=2.5cm