In the adjoining figure AD is median of triangle ABC if BL and CM are drawn perpendicular on AD and AD produced prove that BL=CM
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Answered by
495
hello,
sorry i cant give u the figure,
inΔBDL and ΔCDM,
∠BLD=∠CMD(both equal to 90°)
∠BDL=∠CDM(vetically opposite angles are equal)
BD=CD(AD is median)
∴ΔBDL≡ΔCDM(AAS conguency)
⇒BL=CM(cpct,corresponding parts of congruent triangles)
hence proved
hope this helps,
if u like it please mark it as brainliest
sorry i cant give u the figure,
inΔBDL and ΔCDM,
∠BLD=∠CMD(both equal to 90°)
∠BDL=∠CDM(vetically opposite angles are equal)
BD=CD(AD is median)
∴ΔBDL≡ΔCDM(AAS conguency)
⇒BL=CM(cpct,corresponding parts of congruent triangles)
hence proved
hope this helps,
if u like it please mark it as brainliest
Answered by
82
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