In the adjoining figure AD is parallel to BC. Find the area of trapezium ABCD
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Given : AD || BC
To Find : the area of trapezium ABCD
Solution:
CE = BC - BE
BE = AD = 6 cm
BC = 16 cm
=> CE = 16 - 6 = 10 cm
DE² = CD² - CE²
=> DE² = 26² - 10²
=> DE² = (26 + 10)(26 - 10)
=> DE² = (36)(16)
=> DE² = ( 6²)(4²)
=> DE = 6*4
=> DE = 24 cm
Area of trapezium ABCD = (1/2) (AD + BC) DE
= (1/2)(6 + 16) * 24
= 22 * 12
= 264 cm²
Area of trapezium ABCD = 264 cm²
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