in the adjoining figure, AHK is similar to ABC if ak=10 ,bc=3.5 and hk=7 find ac
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let ac be x
they are similar
therefore their corresponding sides are in proportion
BC/HK=AC/AK
3.5/7=x/10
3.5×10=7x
35=7x
x=35/7
x=5
they are similar
therefore their corresponding sides are in proportion
BC/HK=AC/AK
3.5/7=x/10
3.5×10=7x
35=7x
x=35/7
x=5
Answered by
1
Solution :-
GIVEN:
AK = 10cm, BC = 3.5cm & HK = 7cm
∆AHK ~ ∆ABC
AK/AC = HK/BC
[corresponding sides of similar triangles are proportional]
10/AC = 7/3.5
10/AC = 70/35
10/AC = 10/5
10AC = 10 × 5
AC = (10 × 5) /10
AC = 5 cm
Hence,
The value of AC is 5 cm.
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@GauravSaxena01
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