Math, asked by sujatakedia01, 8 months ago

in the adjoining figure
angle A = 80°,BD and CD are bisectors of angle B and C respectively. then find angle BDC​

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Answered by sharanyalanka7
25

Answer:

130 degrees

Step-by-step explanation:

In triangle ABC angle A + Angle B +angle C = 180 Deg

Angle B +angle C = 180 Deg- angle A

=180-80=100 deg

In triangle BDC angle DBC + angle DCB + BDC = 180 deg

angle DBC = 1/2 angle B ( angular bisectors)

angle DCB = 1/2 angle C

In triangle BDC 1/2 angle B +1/2 angle C + BDC = 180 deg

In triangle BDC 1/2 (angle B + angle C) + BDC = 180 deg

=1/2(100)+BDC= 180 deg

angle BDC = 180 -50

angle BDC= 130 deg

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Answered by josephtherese92
4

Answer:

hope it helps yo

Step-by-step explanation:

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