in the adjoining figure , angle ABC = angle ACB , D and E are points on the sides AC and AB respectively such that BE=CD . prove that
i) triangle EBC =~ triangle DCB
ii) triangle OEB =~ triangle ODC
iii) OB=OC
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in triangle EBC and triangle DCB
BE =DC
BC=BC
angle EBC =DCB
∆EBC=~∆DCB(SAS)
in∆OEB and∆ODC
BE =DE
angleEOB =angleDOB
angleEBO =angleDCO
∆OEB=~∆ODC
OB = OC(CPCT)
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