In the adjoining figure, angle ABC is right-angled at A. Q and R are points on line BC and P is point such that QP||AC and RP||AB. Find angle P.
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Step-by-step explanation:
as AB||RP
taking BR as line crossing on parallel lines
angle ABR = angle BRP
as QP||RC
taking QC as line crossing on parallel lines
angle PQC = angle ACQ
triangle ABC = angles A+B+C
triangle QPR = angles Q+P+R
as angles B=R. C=Q
therefore angle A= Angle P
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