Question

In the adjoining figure,angle ABC similar angle APQ with PQ ll BC. If AQ=QC, prove that 2PQ = BC.
plz with explanation ​

Answer 1

Answer:

In ΔABC,PQ∥BC

∴ By basic Proportionality Theorem, we get

PB

AP

=

QC

AQ

⇒

3

1.5

=

QC

1.3

⇒QC=

15

1.3×3

=

5

13

=2.6cm

Hence, QC=2.6cm

In fig. (ii) given above

In ΔABC,PQ∥BC

∴ By Basic Proportionality Theorem, we get

PB

AP

=

QC

AQ

⇒

6

3

=

5.3

AQ

⇒AQ=

6

3×5.3

=

2

5.3

=2.65cm