Question

in the adjoining figure angle BCD= angle ADC and angleBCA= AngleADB. SHOW THAT I. TRIAngleACD IS CONGRUENT TO TRIANGLE BDC II. BC=AD III. ANGLE A=ANGLE B​

Answer 1

Answer:

in triangle Acd and triangle Bdc

Cd = cd (common)

angle ADC = angle BCD (given)

Angle Bca = angle adb (given)

therefore, triangle Acd I'd congruent to triangle bcd by SAS congruency rule...

Bc=Ad By CPCT

Angle A= angle B by CPCT

THIS IS THE CORRECT SOLUTION .. MARK BRAINLIEST

Answer 2

Answer:

Step by Step explanation:-)

In ∆BDC and ∆ACD,

Angle BCD = Angle ADC

Side CD = Side CD -(Common Side)

Angle BCA = Angle ADB

So, ∆ACD is congruent to ∆BDC -(By A-S-A Test)

Therefore, Side BC = Side AD -(C.S.CT.)

And,

Angle A = Angle B -(C.A.C.T.)

Hence Proved//.