Question

In the adjoining figure angle E=40° and arc AB, arc BC and arc CD all have equal length. Find the measure of angle ACD​

Answer 1

Answer:

.E=40

AB=BC=CD

ACD= 30

Answer 2

Answer:

Here is ur answer dear.....❤❤❤

Note that minor arcs

AD + AB + BC + CD = 360° or....put another way.....

AD + 3BC = 360 → AD = 360 - 3BC (1)

Also

Angle BEC = (1/2) ( BC - AD) sub (1) into this

40 = (1/2) [ BC - (360 - 3BC) ] multiply through by 2 and simplify

80 = 4 BC - 360 add 360 to both sides

440 = 4 BC divide both sides by 4

110° = BC

So, since AB = BC = CD.....then major arc ACD = 330°

And arc AD must = 30°

And since angle ACD is an inscribed angle intercepting this arc...

Its measure is (1/2) arc AD = 15°

hope it helps u....follow me....

plz mark it as a brainliest answer. ...❤❤❤