Question

in the adjoining figure angle QRP=90°,anglePMR= 90°QR=26cm PM= 8 CM THEN FIND THE AREA OF TRIANGLE PQR

Answer 1

Answer:

angle PMR = 90

by pythagoras theorem,

PM² + RM²= PR²

64+36 = PR²

PR= √100

PR = 10cm

in triangle PQR, we know that PR= 10cm and QR = 26cm

area of triangle PQR = 1/2 × b ×h      (where b=QR and h=PR)

area = 1/2×10×26

area = 130cm²

I hope this answer is correct!