In the
adjoining figure
angleB < angleA and angle C<angleD
prove that:AD<BC
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Answered by
1
Step-by-step explanation:
side opposite to bigger angle is bigger in size
therefore CO is bigger than DO
similarly BO is bigger than AO
hence, AD < BC
Answered by
1
Answer:
This is the following answer
Step-by-step explanation:
We know;
Angle B < Angle A and angle C < Angle D
So, Angle B and Angle C will meat at same point so
AD<BC
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