in the adjoining figure, aob is a diameter of the circle and AC=BC then find angle CAB
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Hey there,
NOTE:-I will use D in place of B.
Angle subtended by a chord at the centre is double that of the angle subtended by chord on circumference.
Since diameter subtend 180° at centre therefore it subtend 90° at the circumference.
We can say that ∠ACD=90°
Since it given that AC=DC so the base angles are equal.
⇒∠CAD=∠CDA
In triangle ACD-
∠CAD+∠CDA+∠ACD=180°
Let ∠CAD=∠CDA=∅
therefore 2∅=90°
From this, we can conclude that-
∠CDA=∠CAD=45°
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
NOTE:-I will use D in place of B.
Angle subtended by a chord at the centre is double that of the angle subtended by chord on circumference.
Since diameter subtend 180° at centre therefore it subtend 90° at the circumference.
We can say that ∠ACD=90°
Since it given that AC=DC so the base angles are equal.
⇒∠CAD=∠CDA
In triangle ACD-
∠CAD+∠CDA+∠ACD=180°
Let ∠CAD=∠CDA=∅
therefore 2∅=90°
From this, we can conclude that-
∠CDA=∠CAD=45°
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
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Answer:
CYCLIC QUADRILATREL IS 90
Step-by-step explanation:
CA + BA = 90
THEREFORE CAB = 90
IF THER IS ANY CORRECTION PLS TELL
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