Math, asked by aradhyav622, 3 days ago

In the adjoining figure, AOB is a straight line and COD = 100° Calculate: (i) the values of x and y, when z = 105. (ii) the values of y and z, when x = 24. (iii) the values of x,y and z when y = x + 2
Plz explain me only ii part..​

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Answered by genius150809
3

Answer:

Step-by-step explanation:

ii)x=24

so 2x=48

100+48+y=180

y=180-148=32

x=24

3x=72

72+z=180

z=180-72=108

so z=108

y=32 and z=108

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Answered by CrypticiosCy
4

Answer:

y= 32 degrees

z=108 degrees

Step-by-step explanation:

As x=24

therefore DOB = 24 ×2

which = 48

where as BOE = 24 ×3

which = 72

Now because a straight line make an angle of 180

therefore AB =COD + DOB +COA

and on substituting we get the following equation

180=100+48+COA

By transposing

therefore COA = 180-100-48

COA = 32

therefore y = 32 degrees

=> that AB being 180

and BOE = 72

we get the equation

AB=BOE+AOE

substituting the values we get

180=72+AOE

transposing the values we get

180-72=AOE or 180-72=z

therefore z= 108 degrees

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