Question

In the adjoining figure, AOB is the diameter of the circle
and O is the centre of the circle. The radius OC is
perpendicular on AB. If Pis any point on minor arc CB,
We us write by calculating the values of angle BAC and angle APC​

Answer 1

Answer:

but where is figure how will we answer

Answer 2

Answer:

Question :-

In the adjoining figure, AOB is the diameter of the circle and O is the centre of the circle. The radius OC is perpendicular on AB. If P is any point on minor arc CB, we us write by calculating the values of angle BAC and angle APC.

Answer :-

AB $\perp$ OC

∴ ∠AOC = ∠BOC = 90°

∠AOC is an Isosceles triangle

So, AO = OC

∴ ∠OAC = ∠OCA

Now, ∠OAC + ∠OCA = 90° [ $\because$ ∠AOC = 90° ]

or, ∠OAC + ∠OAC = 90°

∴ 2∠OAC = 90°

or, ∠OAC = ∠BAC = 45°

Similarly ∠ABC = 45°

Again, ∠ABC and ∠APC are same circular angle

∴ ∠APC = ∠ABC = 45°