Question

In the adjoining figure ∠AOC = 2x- 40˚ and ∠BOC= x+10˚,

find the value of x.



A O B

C​

Answer 1

Answer:

$< aoc = < boc(vertcally \: opposite \: angle) \\ \\ 2x - 40 = x + 10 \\ 2x - x = 10 + 40 \\ x = 50$