in the adjoining figure AOC is 60 degree then DOB is
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Answer:
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Step-by-step explanation:
Answered by
0
Step-by-step explanation:
Since AOB is a straight line, we have
∠AOE+∠BOE=180
o
=3x
o
+72
o
=180
o
⇒3x
o
=108
o
⇒x=36
o
We also know that
∴∠AOC+∠COD+∠BOD=180
o
(∵ straight angle)
⇒x
o
+90
o
+y
o
=180
o
⇒36
o
+90
o
+y
o
=180
o
y
o
=180
o
−126
o
=54
o
∴∠AOC=36
o
,∠BOD=54
o
and ∠AOE=108
o
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