In the adjoining figure, area of parallelogram ABCD = 48 cm sq and FC||AB. Find, i)area of ||gm ABEF and area of ΔEAB
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⇒ In given figure, we can see that parallelogram ABCD and parallelogram ABEF both are lies between same parallel line that is FC and AB.
⇒ And parallelogram ABCD and ABEF contains same base that is AB.
⇒ So, we know that parallelogram on same base and between same parallels are equal in area.
⇒ So, Area(ABCD)=Area(ABEF) ------ ( 1 )
⇒ We have given Area(ABCD)=48 cm
2
From (1) we get,
Area of parallelogram ABEF=48 cm
2
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