In the adjoining figure area of parallelogram abcd is 40 cm square if pq is a median of a triangle cdp then find the area of pdq
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Area of ΔPDQ = 10 cm² In the adjoining figure area of parallelogram abcd is 40 cm² and pq is a median of a triangle cdp
Step-by-step explanation:
Lets Draw PM ⊥ CD
Area of Parallelogram ABCD = CD * PM = 40 cm²
Area of Δ CPD = (1/2) CD * PM
= (1/2) * 40
= 20 cm²
Area of ΔPDQ = (1/2) QD * PM
QD = QC = CD/2 ( as PQ is Median of ΔCDP)
= (1/2) (CD/2) * PM
= (1/4) CD * PM
= (1/4) * 40
= 10 cm²
Area of ΔPDQ = 10 cm²
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