Question

In the adjoining figure, BE and CE are bisectors of ABC and ACD respectively. If BEC = 25°, then BAC is equal to :- ∠ ∠ ∠​

Answer 1

Step-by-step explanation:

Extend the line BC to E

BD and CD are angular bisectors,

∴∠ABD=∠DBC=x and ∠ACD=∠DCE=y

∠ABC=2x and ∠ACE=2y

Consider △ABC,

∠ACE=∠ABC+∠BAC ------exterior angle is equal to sum of interior opposite angle

2y=2x+∠A

y−x=

2

∠A

------(i)

Consider △BCD,

∠DCE=∠DBC+∠BDC ------exterior angle is equal to sum of interior opposite angle

y=x+∠D

y−x=∠D------(ii)

From(i) and (ii)

∠D=

2

1

∠A

Answer 2

Answer:

(a) 50°

Step-by-step explanation:

Explanation: In triangle BEC

<BEC + <EBC = <ECD (Exterior angle property)

<BEC =< ECD - <EBC

In  triangle ABC

<ABC + <BAC = <ACD

<ABC + 2 <EBC = 2 <ECD

<ABC = 2(< ECD - <EBC)

<ABC = 2( BEC)

<ABC = 50

Hope it is helpful.. plz mark me as brainliest.. and friends plz give thanks if it is helpful to u guys.. Have a great day..