Question

in the adjoining figure BM perpendicular AC and dn perpendicular ac if bm equal dn prove ac bisect bd

Answer 1

Thank you for asking this question. Here is your answer:

First of all we will take the point of intersection

And then in the triangles  BOM and DON

BM = DN (this is given in the question)

∠BOM = ∠DON

∠BMO = ∠DNO (it will be equal to 90°)

BO = DO

or you can say AC bisects BD

If there is any confusion please leave a comment below.