in the adjoining figure bnn DM are perpendicular to the line segment AC is b m is equal to DM prove that AC bisects BD
Attachments:
Answers
Answered by
67
To prove
DE=EB
Proof In tri EMB AND tri END
angle EMB=END (each 90)
"""""" MEB=NED (VOA)
side BM=DN(given)
BY A AS Congruencey
:;triEMB congruent tri END
so BE=DE (cpct)
proved
[tex][/tex]
DE=EB
Proof In tri EMB AND tri END
angle EMB=END (each 90)
"""""" MEB=NED (VOA)
side BM=DN(given)
BY A AS Congruencey
:;triEMB congruent tri END
so BE=DE (cpct)
proved
[tex][/tex]
Similar questions