in the adjoining figure bnn DM are perpendicular to the line segment AC is b m is equal to DM prove that AC bisects BD
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To prove
DE=EB
Proof In tri EMB AND tri END
angle EMB=END (each 90)
"""""" MEB=NED (VOA)
side BM=DN(given)
BY A AS Congruencey
:;triEMB congruent tri END
so BE=DE (cpct)
proved
[tex][/tex]
DE=EB
Proof In tri EMB AND tri END
angle EMB=END (each 90)
"""""" MEB=NED (VOA)
side BM=DN(given)
BY A AS Congruencey
:;triEMB congruent tri END
so BE=DE (cpct)
proved
[tex][/tex]
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