Math, asked by dhootshankar, 5 months ago

In the adjoining figure, CD is an altitude of triangelABC. DE and
DF are perpendiculars from D on the sides AC and BC
respectively such that DE = DF. Show that triangleDEC and triangle DFC
are congruent.

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Answers

Answered by ansariarhum25

0

Step-by-step explanation:

Given:

DE ~ DF

Lets take ∆ CDE & ∆ CDF

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