in the adjoining figure, ce is a tangent and ∠abc=93°, ∠dce=35°
find ∠adc, ∠cad, ∠acd
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/_DAC = /_DCE [Alternate segment theorem]
/_DAC = 35°
/_ABC + /_ADC = 180° [Opposite angles of a cyclic quadrilateral]
=> /_ADC = 180 - 93
=> /_ADC = 87°
/_DAC + /_ADC + /_ACD = 180° [Angle Sum Property]
=> /_ACD = 180 - 87 - 35
=> /_ACD = 58°
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