In the adjoining figure,
chord AB and chord CD
of a circle with centre 'o',
intersect is point Q.
If m(arc AD) = 25°, and m(arc BC) = 31º.
Find angleBQC.
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13
Answer:
28°
Step-by-step explanation:
Angle BQC = 1 [ m( arc DA ) + m( arc BC ) ]
2
= 1 ×[ 31 + 25 ]
2
= 1 × 56
2
= 28°
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