in the adjoining figure chord ac and chord de intersect at point b if angle abe=108 degree andm(arc ae)=95 degree then find m(arc dc)
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Step-by-step explanation:
We know that if two chords intersect each other in the interior of the circle, then the measure of the angle between them is half the sum of measures of the arc intercepted by the angle and it's opposite angles.
Therefore, angle ABE= 1/2 [m (arc AE) + m (arc DC)]
m (arc AE ) + m ( arc DC ) = 2 angle ABE
95° + m (arc DC ) = 2 × 108°
m( arc DC ) = 216°-95°
= 121°
Thus the measure of arc DC is 121°
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