Question

In the adjoining figure, circle with centre D touches the sides
of ACB at A and B. If /ACB = 52°, find the measure of /ADB.​

Answer 1

Answer:

128°

Step-by-step explanation:

Sum of all the angles in quadrilateral = 360°

Hence, / ACB = 360 - 90 -90 - 52 = 128°