Question

In the adjoining figure ,DE||BC,then find x

Answer 1

Given :-

• DE || BC .
• AD = (2x - 1)
• DB = (x - 3)
• AE = (2x + 5)
• EC = (x - 1)

To Find :-

• value of x ?

Solution :-

since DE || BC .

so,

→ AD / DB = AE / EC (BPT)

putting values we get,

→ (2x - 1) / (x - 3) = (2x + 5) / (x - 1)

→ (2x - 1)(x - 1) = (x - 3)(2x + 5)

→ 2x² - 2x - x + 1 = 2x² + 5x - 6x - 15

→ 1 - 3x = - x - 15

→ -3x + x = -15 - 1

→ (-2x) = (-16)

→ x = 8 (Ans.)

Hence, value of x will be 8.

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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