In the adjoining figure,DE is paralel to AB , AD =7cm,CD=5cm and BC =18cm .find BE and CE
Attachments:
Answers
Answered by
53
Help u ......
....
............
....
............
Attachments:
Answered by
58
Since DE is parallel to AB,
By BPT,
Triangle ABC is similar to triangle DEC.
Thus,
CD/DA=CE/EB
7x+5x = 18
X= 3/2
Ce= 5x = 15/2cm
Be=21/2cm
By BPT,
Triangle ABC is similar to triangle DEC.
Thus,
CD/DA=CE/EB
7x+5x = 18
X= 3/2
Ce= 5x = 15/2cm
Be=21/2cm
Similar questions