In the adjoining figure, DE || QR and AP and BP are bisectors of ∠EAB and ∠RBA respectively. Show that ∠APBis a right angle.
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Step-by-step explanation:
Given: DE∥QR, AP bisects ∠EAB, BP bisects ∠RBA
Since, DE∥QR
∠EAB+∠RBA=180
1/2(∠EAB+∠RBA)=90
∠PAB+∠PBA=90 (AP bisects ∠EAB, BP bisects ∠RBA)
Now, In △PAB
∠PAB+∠PBA+∠APB=180
90 +∠APB=180
∠APB=90∘
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