Question

in the adjoining figure, determine: sin alfa+sin bitta​

Answer 1

Step-by-step explanation:

sin ( α ) = AB = x.

BC √13

sin ( β ) = AC = 5 - x

BC √13

Now,

$\sin( \alpha ) + \sin( \beta) = \frac{x}{ \sqrt{13} } + \frac{5 - x}{ \sqrt{13} }$

$\sin( \alpha ) + \sin( \beta ) = \frac{x + 5 - x}{ \sqrt{13} }$

$\sin( \alpha ) + \sin( \beta ) = \frac{5}{ \sqrt{13} }$

Hope it helps