in the adjoining figure find angle ACD, if ab =bc=ac
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In the above triangle AB = BC = AC
So ∆ABC is a equilateral triangle
Here angle ACD is exterior angle
In a triangle exterior angle = sum of two opposite interior angles and here all angles are 60°(Because sum of three angles of traingle is 180° and all the three sides are equal)
So exterior angle ACD = 60°+60° = 120°
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