In the adjoining figure, find sin x
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Answer:
√5/3
Step-by-step explanation:
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Answered by
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Step-by-step explanation:
AB = sqrt{5}, AC = 3 and BC = ?
by Pythagoras Theorem
AC^2 = AB^2 + BC^2
(3)^2 = (sqrt{5})^2 + BC^2
9 = 5 + BC^2
9 - 5 = BC^2
sqrt{4} = BC
BC = 2
Sin x = Perpendicular/Hypothenuse
Sin x = AB/AC
Sin x = sqrt{5}/3
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